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C语言编程求问 从键盘输入一个整数n(0<n<=20),然后...

#include int main(void) { int n,str[9],i=0,k,temp,index; char c; printf("Input n: "); scanf("%d",&n); printf("Input %d integers: ",n); for(i=0;i

#include void main() { int n,i,j; printf("请输入n(0

#include int main() {int a[100],n,i,j,t; scanf("%d",&n); for(i=0;i

#include int main() {int i,j,n,a[100]; scanf("%d",&n); for(i=0;i

#include int main() {int n,i,j,t,a[200]; scanf("%d",&n); for(i=0;i

#include #include #include #include #include #include using namespace std; int main() { int M,N; while(scanf("%d%d",&M,&N)==2) { double sum = 0; for(int i=M;i

首先说下你错在哪里: 从上图可以看出来是每一次循环计算一次结果,所我的想法是使用数组去记录每次结果,后再打印,代码如下: #include #include #include int main(void){int ri, repeat;int n, i, j;int flag[2] = {0};int a[6][6];scanf_s("%d",...

#include"stdio.h" void main() { int a[9]={1,12,123,1234,12345,123456,1234567,12345678,123456789}; int n,ans=0; printf("Input a number N(0

#include #define n 100 using namespace std; int main() { int a[n]={2,3},i,x; scanf("%d",&x); for (i=0;i

求大于M且紧靠M的N个素数并存入数组中然后输出,M和N需从键盘输入: #include #include int vanum(int m){ Int i,n=0; for(i=2;i

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